Three charges $-q_{1,}+q_2\text{\hspace{0.17em}\hspace{0.17em}and\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}-q_3$  are placed as shown in the figure. The x-component of the force on $-q_{1,}$ is proportional to 
                  
 

               
${\text{F}}_{\text{2}}\text{=}$Force applied by  ${\text{q}}_{\text{2}}\text{\hspace{0.17em}\hspace{0.17em}on\hspace{0.17em}\hspace{0.17em}}-{\text{q}}_{\text{1}}$
${\text{F}}_3\text{=}$Force applied by  $(-{\text{q}}_{\text{3}})\text{\hspace{0.17em}\hspace{0.17em}on\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}-{\text{q}}_{\text{1}}$
x- component of Net force on ${\text{-q}}_1$ is 
${\text{F}}_{\text{x}}{\text{= F}}_{\text{2}}{\text{+ F}}_{\text{3}}\text{\hspace{0.17em}sin θ = k}\frac{{\text{q}}_{\text{1}}{\text{q}}_{\text{2}}}{{\text{b}}^{\text{2}}}\text{ + k.}\frac{{\text{q}}_{\text{1}}{\text{q}}_3}{{\text{a}}^{\text{2}}}\text{sin θ}$