Three charges +Q, q,+Q are placed respectively at a distance O, d2 and d from the origin. If the net force experienced by +Q , placed at x=0 , is zero then the value of q is

For equilibriumF→A+F→B=O F→A=−F→B KQQd2=−KQqd/22 Qd2=−q4d2 q=−Q4

Three charges +Q, q,+Q are placed respectively at a distance O, d2 and d from the origin. If the net force experienced by +Q , placed at x=0 , is zero then the value of q is

For equilibriumF→A+F→B=O F→A=−F→B KQQd2=−KQqd/22 Qd2=−q4d2 q=−Q4

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Three charges $+ Q, q, + Q$ are placed respectively at a distance $O, (\frac{d}{2})$ and $(d)$ from the origin. If the net force experienced by $+ Q$ , placed at $x = 0$ , is zero then the value of $q$ is

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$+ Q / 2$

$- Q / 2$

$- Q / 4$

$+ Q / 4$

answer is C.

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For equilibrium ${\vec{F}}_{A} + {\vec{F}}_{B} = O$

${\vec{F}}_{A} = {\vec{- F}}_{B} \frac{K Q Q}{d^{2}} = \frac{- K Q q}{{(d / 2)}^{2}} \frac{Q}{d^{2}} = \frac{- q (4)}{d^{2}} q = - \frac{Q}{4}$

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Three charges +Q, q,+Q are placed respectively at a distance O, d2 and d from the origin. If the net force experienced by +Q , placed at x=0 , is zero then the value of q is

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Three charges $+ Q, q, + Q$ are placed respectively at a distance $O, (\frac{d}{2})$ and $(d)$ from the origin. If the net force experienced by $+ Q$ , placed at $x = 0$ , is zero then the value of $q$ is