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Three chords $AB, CD$ and $EF$ of a circle are respectively $3 cm, 3.5 cm$ and $3.8 cm$ away from the centre. Then which of the following is correct?

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AB > CD > EF

AB < CD < EF

AB = CD = EF

AB = CD < EF

answer is A.

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Detailed Solution

Given that three chords

AB, CD

and

EF

of a circle are

3 cm, 3.5 cm

and

3.8 cm

away from the centre respectively.
Question Image

Here, three chords are away from the center.
From the figure, we can observe that the chord which is nearer to diameter is longer than the chords comparatively farther from diameter.
So,

A B > C D > E F

, where, AB = 3cm, CD = 3.5cm and EF = 3.8cm.
Hence, the correct option is 1.

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