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Three coherent waves having amplitude 12mm, 6 mm and 4 mm arrive at a given point with successive phase difference of $\frac{π}{2}$ . Then the amplitude of the resultant wave is

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4.8 mm

7 mm

5 mm

10 mm

answer is B.

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Detailed Solution

Phase difference between 12mm & 4mm is $π$ rad For them
$y_{n e t} = 12 - 4 = y_{1}$
So it is the case of $y_{1} = 8 mm & y_{2} = 6 mm with a phase difference ϕ = \frac{π}{2}$
$y_{net} = \sqrt{y_{1}^{2} + y_{2}^{2}} = 10 mm$

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