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Three coins are tossed simultaneously 300 times with the following frequencies of different outcomes:

Find the probability of getting at least two heads.

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\frac{34}{75}

\frac{34}{55}

\frac{34}{65}

\frac{34}{70}

answer is A.

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Detailed Solution

Given that, three coins are tossed for 300 times and the number of heads recorded as:

We have to find the probability of getting atleast two heads.
The total outcome is n(S) = 300.
The favorable outcome will be the sum of frequencies of 2 heads and 3 heads.

n (A) = 41 + 96

\Rightarrow n (A) = 136

Probability of an event A is given by,
P(A) =

\frac{Number of favourable outcomes n (A)}{Total number of outcomes n (S)}

Substitute the value in the formula of probability,

P (E) = \frac{136}{300}

\Rightarrow P (E) = \frac{34}{75}

Thus, the probability of atleast 2 heads is

\frac{34}{75} .

Hence, option 1 is correct.

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