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Three cubes of volume $27 cm 3$ each are joined end-to-end to form a solid. What is the surface area of the cuboid so formed?

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126 cm 2

80 cm 2

100 cm 2

95 cm 2

answer is A.

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Detailed Solution

Given are three cubes of volume

27 cm 3

.
We have the following formulae,
Volume of cube =

a 3

The total surface area of cuboid =

2 l b + b h + h l

The length of the cube will be,

a 3 = 27 a = 3 c m

Then the dimensions of the cuboid will be,

l = 3 a = 9 b = a = 3 h = a = 3

The surface area of the cuboid will be,

= 2 (9 × 3 + 3 × 3 + 3 × 9) = 2 (27 + 9 + 27) = 2 (63) = 126 cm 2

Thus, the surface area of the cuboid is

126 cm 2

.
Therefore the correct option is 1.

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