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Three cuboidal dielectric slabs of equal volume and depth (into the plane of diagram) are placed inside a parallel plate capacitor to fill it completely as shown. The dimensions of the slabs with dielectric constant $K_{2} & K_{3}$ are identical. What is the ratio of electric field in the dielectric of constant $K_{1}$ to the electric field in the dielectric of constant $K_{3}$ ?

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$\frac{K_{1} (K_{2} + K_{3})}{2 K_{2} K_{3}}$

$\frac{K_{1} (K_{2} + K_{3})}{4 K_{2} K_{3}}$

$\frac{K_{2} + K_{3}}{4 K_{2}}$

$K_{1} / K_{3}$

answer is B.

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