Three dice are rolled simultaneously. The probability that the sum of the numbers on them is 16 is

The random experiment is " Rolling three dice"

Let $S$ be the sample space, $n\left(S\right)=6^3=216$

Let $E$ be the event of getting " total 16"

$E=\left\{\left(6,6,4\right),\left(6,4,6\right),\left(4,6,6\right),\left(6,5,5\right),\left(6,5,6\right),\left(5,5,6\right)\right\}$

There are 6 favoruable cases 

Hence, $n\left(E\right)=6$

Therefore, the probability is $P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{6}{216}=\boxed{\frac{1}{36}}$