Three different coins are tossed together. Find the probability of getting 

(𝑖) exactly two heads 

(𝑖𝑖) at least two heads 

(𝑖𝑖𝑖) at least two tails

Given that, 

Three different coins are tossed together 

The possible outcomes are 

= 𝐻𝐻𝐻, 𝑇𝑇𝑇, 𝐻𝐻𝑇, 𝑇𝑇𝐻, 𝐻𝑇𝑇, 𝑇𝐻𝐻, 𝐻𝑇𝐻. 𝑇𝐻𝑇

 Number of possible outcomes = 8 

(𝑖)Probability of getting exactly two heads Number of favourable outcomes = 3

$\begin{array}{r}P\left(H\right)=\frac{\text{ Number of favourable outeomes }}{\text{ Total Number of outeomes }}\\ =\frac{3}{8} \end{array}$

(𝑖𝑖)Probability of getting at least two heads

Number of favourable outcomes = 4

$\begin{array}{r}P\left(A\right)=\frac{4}{B}\\ =\frac{1}{2} \end{array}$

(𝑖𝑖𝑖)Probability of getting at least two tails

Number of favourable outcomes = 4

$\begin{array}{r}P\left(B\right)=\frac{4}{8}\\ =\frac{1}{2}\end{array}$