Three discs A, B and C having radii 2m, 4m and 6m respectively are coated with carbon black on their outer surface. The wavelengths corresponding to the maximum intensity are 300nm, 500nm and 800 nm respectively. The power radiated by them are $Q_{A}, Q_{B}$ AND $Q_{C}$ respectively. Then

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$Q_{A} i s \max i m u m$

$Q_{B} i s \max i m u m$

$Q_{C} i s \max i m u m$

$Q_{A} = Q_{B} = Q_{C}$

answer is B.

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Detailed Solution

$Q = Q = σ A T^{4},$ Here $A = π r^{2}$
According to wien’s law $λ_{m} T = b$ Or $T = (b / λ_{m})$
$Q = σ (π r^{2}) {(b / λ_{m})}^{4} O r, Q o r \frac{r^{2}}{λ_{m}^{4}} Q_{B} > Q_{C} > Q_{A}$

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