Three families of lines are as follows 
$$\begin{gathered} \left(i\right)2x+3y+1+k_1(2x+4y+4)=0, \\ \left(ii\right)(3+6\tan \theta )x+(4+4\tan \theta )y+4+\tan \theta =0, \\ \left(iii\right)(x+y+\lambda )+k_3(2x+y+1)=0 \end{gathered}$$
Then the values of $\lambda$ so that 3 families have a common member is  $\frac{p}{q}$, where p and q are positive integers and  co-prime to each other, then the value of $(4q-3p)$ is