Three forces 202 N , 202 N and 40N are acting along X, Y and Z – axis respectively on a 102 kg mass at rest at origin. The magnitude of its displacement after 5s is,

a=Fm=(202)2+(202)2+402102=402102=4ms-2 s=12at2 =12×4×52=50m

Three forces 202 N , 202 N and 40N are acting along X, Y and Z – axis respectively on a 102 kg mass at rest at origin. The magnitude of its displacement after 5s is,

a=Fm=(202)2+(202)2+402102=402102=4ms-2 s=12at2 =12×4×52=50m

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Three forces $20 \sqrt{2} N$ , $20 \sqrt{2} N$ and 40N are acting along X, Y and Z – axis respectively on a $10 \sqrt{2} k g$ mass at rest at origin. The magnitude of its displacement after 5s is,

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$50 m$

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$a = \frac{F}{m} = \frac{\sqrt{{(20 \sqrt{2})}^{2} + {(20 \sqrt{2})}^{2} + 40^{2}}}{10 \sqrt{2}} = \frac{40 \sqrt{2}}{10 \sqrt{2}} = 4 m s^{- 2}$

$s = \frac{1}{2} a t^{2}$ $= \frac{1}{2} \times 4 \times 5^{2} = 50 m$

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Three forces 202 N , 202 N and 40N are acting along X, Y and Z – axis respectively on a 102 kg mass at rest at origin. The magnitude of its displacement after 5s is,

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Three forces $20 \sqrt{2} N$ , $20 \sqrt{2} N$ and 40N are acting along X, Y and Z – axis respectively on a $10 \sqrt{2} k g$ mass at rest at origin. The magnitude of its displacement after 5s is,