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Three forces act on a wheel of radius 20cm as shown in fig

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The torque produced by the force of 9N is zero

The torque produced by the force of 4N is 0.8 Nm anticlockwise

The net torque produced by the forces is 1.8 Nm clockwise

The torque produced by the force of 8N is 0.8 Nm clockwise

answer is A, B, D.

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Detailed Solution

$0.2 \times 8 \sin (90 + 60) c w = 0.8$

$4 \times 0.2 \sin 90 A c w = 0.8$

$4 \times 2 \sin 90 c w = 1.8 c w$

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