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Q.

Three identical blocks lie at rest along a line on a smooth horizontal surface. The separation between any two adjacent blocks is L. The first block is moved with a velocity  υ  towards the second block at time t=0.  The coefficient of restitution for collision between any two blocks is 1/3. Then the third block will start moving at time  t=NLu. Find the value of N.

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answer is 2.5.

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Detailed Solution

First sphere will take a time t1 to start motion in second sphere on colliding with it, where t1=Lu.

Now speed of second sphere will be υ2=u2(1+e)=23u

Hence, time taken by second sphere to start motion in third sphere t2=L2/3u=3L2u.

 Totalotimet=t1+t2=Lu+3L2u=5L2u

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