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Q.

Three identical bulbs are connected as shown in figure : 

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Each bulb dissipate a maximum power P. Assuming at least one of the bulbs is dissipating maximum power, then:

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a

The total power dissipated of the circuit is 3P/2

b

The total power dissipated of the circuit is 3P

c

The currents in bulbs B1, B2 and B3 are in ratio 2:1:1

d

The current through each bulb is same

answer is B, D.

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Detailed Solution

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If i in the current in bulb B1, then it will divide equally in bulbs B2 and B3

Option (c) is wrong, option (d) is correct.

Also P=i2R. Bulb B1 glows with maximum power

Power dissipated in bulbs B2 or B3 ,

P'=i22R=P4.

Thus total power =P+P4+P4=3P2 .

Option (b) is correct, option (a) is wrong.

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