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Three identical capacitors are charged by connecting them in parallel across a battery of V volt. They are then allowed to discharge via resistor R₁, R₂ and R₃. Here, Q charge versus t time graphs are shown. Then,

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R₁ is smallest

R₂ is smallest

R₃ is smallest

$R_{3} > R_{2} < R_{1}$

answer is C.

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Detailed Solution

$q = q_{0} e^{- t / CR}$ .

At a given time

$q_{1} > q_{2} > q_{3} \Rightarrow R_{1} > R_{2} > R_{3}$

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