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Three identical particles are joined together by a thread as shown in figure. All the three particles are moving in a horizontal plane. If the velocity of the outer most particle is $v_{0}$ then the ratio of tensions in the three sections of the string is

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3 : 5 : 7

3 : 4 : 5

7 : 11 : 6

3 : 5 : 6

answer is D.

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Detailed Solution

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$T_{1} = m .3 l ω^{2} = 3 m l ω^{2}$

$T_{2} = 5 m l ω^{2}$

$T_{2} - T_{1} = m .2 l ω^{2}$

$T_{3} - T_{2} = m l ω^{2}$

$T_{3} = 6 m l ω^{2}$

$T_{1} : T_{2} : T_{3} = 3 m l ω^{2} : 5 m l ω^{2} : 6 m l ω^{2}$

$T_{1} : T_{2} : T_{3} = 3 : 5 : 6$

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