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Three invisible radiations X, Y and Z are passed through an electric field. X goes straight, Y deviates towards the positive end while Z deviates towards the negative end. The particles present in X, Y and Z and the e/m ratio for X are

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\begin{matrix} X & Y & Z & e/m ratio for 'X' \\ N e u t r o n s & E l e c t r o n s & Protons & 0 \end{matrix}

\begin{matrix} X & Y & Z & e/m ratio for 'X' \\ α - p a r t i c l e s & β - p a r t i c l e s & γ - r a y s & 0 \end{matrix}

\begin{matrix} X & Y & Z & e/m ratio for 'X' \\ α - p a r t i c l e s & β - p a r t i c l e s & γ -rays & 1 \end{matrix}

\begin{matrix} X & Y & Z & e/m ratio for 'X' \\ N e u t r o n s & E l e c t r o n s & Protons & 1 \end{matrix}

answer is A.

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Detailed Solution

$\begin{matrix} X & Y & Z & e/m ratio for 'X' \\ N e u t r o n s & E l e c t r o n s & Protons & 0 \end{matrix}$

X goes straight implying X is neutral hence X is neutron, Y deviates towards the positive end hence Y is electron while Z deviates towards the negative end Z is proton implies Z.

Because neutron has no charge so, e/m is “0”.

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