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Three large box are kept stationary over one other as shown in figure. A horizontal force 20 N acts on middle block as shown in figure. Then select the correct statement(s).

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Acceleration of lowest block is 4.5 ms^-2

Acceleration of upper most block is 2 ms^-2

Friction between middle and lower block is 12 N.

Friction between middle and upper block is 2 N.

answer is A, B, D.

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Detailed Solution

$(f_{1}) maximum = 0 .2 \times 10 = 2 N$

$(f_{2}) maximum = 0 .8 \times 20 = 16 N$

$(f_{3}) maximum = 0 .3 \times 30 = 9 N$

So, acceleration of the lowest block is

$a_{3} = \frac{f_{2} - f_{3}}{1} = 4 .5 {ms}^{- 2}$

Acceleration of upper most block is

$a_{1} = \frac{f_{1}}{1} = 2 {ms}^{- 2}$

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