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Three large identical conducting parallel plates carrying charge $+ Q, - Q a n d + 2 Q,$ respectively, are placed as shown in figure. If $E_{A}, E_{B} a n d E_{C}$ refer to the magnitudes of the electric fields at points A, B, and C, respectively, then

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$E_{A} = 0 a n d E_{B} > E_{C}$

$E_{A} > E_{B} > E_{C}$

$E_{A} = 0 a n d E_{B} = E_{C}$

$E_{A} = E_{B} > E_{C}$

answer is D.

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Detailed Solution

$E_{P} = 0$ (since it is a point inside conductor)

or $K [\frac{Q - q}{2 ε_{0}} - \frac{q}{2 ε_{0}} + \frac{q}{2 ε_{0}} + \frac{Q - q}{2 ε_{0}} - \frac{(Q + q)}{2 ε_{0}} - \frac{(Q - q)}{2 ε_{0}}] = 0$

or q= 0

Clearly $= E_{A} = 0$

$E_{B} = - \frac{2 K Q}{2 ε_{0}} = \frac{- K Q}{ε_{0}}$

$E_{C} = \frac{2 K Q}{2 ε_{0}} = \frac{K Q}{ε_{0}}$

In magnitude, $E_{B} = E_{C}$

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