Three lines are 

   $\begin{array}{l}{L}_1:\overrightarrow{r}=\lambda \hat{i},\lambda \in \mathrm{ℝ}\\ L_2:\overrightarrow{r}=\hat{k}+\mu \hat{j},\mu \in \mathrm{ℝ}\\ L_3:\overrightarrow{r}=\hat{i}+\hat{j}+v\hat{k},v\in \mathrm{ℝ}\end{array}$

are given . For which point(s) Q on L2 can we find a point P on L1 and a point R on L3 so that P, Q and R are collinear

$$\begin{gathered} \begin{array}{l}General points on the given lines are P(\lambda ,0,0),Q(0,\mu ,1),R(1,1,\gamma )\\ \text{ If P,Q,R collinear }\\ The direction ratios of PQ and PR are proportional \\ \Rightarrow \frac{\lambda }{\lambda -1}=\frac{-\mu }{-1}=\frac{-1}{-\gamma }\\ \Rightarrow \mu =1+\frac{1}{\lambda -1}=\frac{1}{\gamma }\Rightarrow \mu \ne 1,0\end{array} \end{gathered}$$

$\text{Among the options 2,4 are correct}$