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Three long straight and parallel wires carrying currents are arranged as shown in figure. The wire 'B' which carries a current of 5A is so placed that it experiences no force. The distance of wire 'B' from A is then

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9 cm

7 cm

5 cm

3 cm

answer is A.

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Detailed Solution

F_{1} = F_{2}

$\frac{μ_{0} i_{1} i_{2} l}{2 π x} = \frac{μ_{0} i_{2} i_{3} l}{2 π (r - x)}$

$\Rightarrow \frac{i_{1}}{x} = \frac{i_{3}}{r - x}$

$\frac{15}{x} = \frac{10}{15 - x}$

$x = 9 cm$

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