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Three masses 700g, 500g and 400g are suspended at the end of the spring and they are in equilibrium. When the 700g mass is removed, the system oscillates with a period of 3s. when the 500g mass is also removed, it will oscillate with a period of

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1 s

2 s

3 s

$\sqrt{\frac{12}{5}} s$

answer is B.

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Detailed Solution

$T = 2 π \sqrt{\frac{m}{K}}$

when 700 gm is removed mass oscillating is 900 gm and 500 gm is also removed mass oscillates is 400 gm

$\frac{T_{1}}{T_{2}} = \sqrt{\frac{m_{1}}{m_{2}}} = \sqrt{\frac{900}{400}} = \frac{3}{2} \frac{3}{T_{2}} = \frac{3}{2}; T_{2} = 2 s e c$

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