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Three masses are placed on the x -axis: 300 g at origin, 500 g at x = 40 cm and 400 g at x = 70cm, The distance of centre of mass from the origin is:

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45 cm

50 cm

40 cm

30 cm

answer is C.

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Detailed Solution

$X_{c m} = \frac{m_{1} x_{1} + m_{2} x_{2} + m_{3} x_{3}}{m_{1} + m_{2} + m_{3}}$

$X_{cm} = \frac{300 \times 0 + 500 \times 40 + 400 \times 70}{1200} = 40 cm$

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