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Three metallic bars A, B and C are arranged as shown in the figure. Number density of free electrons in the three bars are in ratio,

$N_{A} : N_{B} : N_{C} = 1 : 2 : 3,$ ratio of resistivities of the bar is $ρ_{A} : ρ_{B} : ρ_{C} = 2 : 3 : 1,$ lengths are in ratio $l_{A} : l_{B} : l_{C} = 2 : 2 : 3$ and radii are in the ratio $r_{A} : r_{B} : r_{C} = 1 : 2 : 3$ as shown.
Choose the correct alternative (s).

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Power dissipated in A is $4 \sqrt{2}$ times the geometric mean of powers dissipated in B and C.

Electric fields in the wires A, B and C are related as $32 E_{B}^{2} = 81 E_{A} E_{C} .$

Drift speed of electrons in the wire B is arithmetic mean of drift speeds in wire A and C.

Potential differences across the wires are related as $V_{A} : V_{B} : V_{C} = 24 : 9 : 2 .$

answer is A, B, D.

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