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Q.

Three moles of an ideal monoatomic gas performs a cycle 1234as shown. The gas temperatures in different states are T1=400K,T2=800K,T3=2400K and T4=1200K .The work done by the gas during the cycle is
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a

3600 R

b

2400 R

c

1200 R

d

2000 R

answer is C.

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Detailed Solution

1→2 and 3→4 are isochoric process. Therefore, work done is zero
Wtotal =W23+W41=P2V3V2+P4V1V4=nRT3T2+nRT1V4=nRT3T2+T1T4 =80nR=2400R

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