Three moles of $\mathrm{AgCl}$ get precipitated when one mole of an octahedral coordination compound with the empirical formula ${\mathrm{CrCl}}_3·3{\mathrm{NH}}_3.3{\mathrm{H}}_2\mathrm{O}$ reacts with an excess silver nitrate. The number of chloride ions satisfying the secondary valency of the metal ion is ____

The amount of Cl^- present in the ionization sphere is equal to the amount of precipitated AgCl.

$\left[\mathrm{Cr}{\left({\mathrm{H}}_2\mathrm{O}\right)}_3{\left({\mathrm{NH}}_3\right)}_3\right]{\mathrm{Cl}}_3\to {\left[\mathrm{Cr}{\left({\mathrm{H}}_2\mathrm{O}\right)}_3{\left({\mathrm{NH}}_3\right)}_3\right]}^{3+}+3{\mathrm{Cl}}^{-}\stackrel{{\mathrm{AgNO}}_3}{\to }\mathrm{AgCl}$

           1 mole                                       1 mole                     3 mole             3 mole

Due to the absence of Cl^- in the coordination sphere. The answer is zero as a result.