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Q.

Three particles, each of mass m, are placed at corners of right angled triangle as shown in Fig. if OA=a and OB=b, the position vector of the center of mass is (here I and j are unit vectors along x and y axes respectively).

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a

23(ai+bj)

b

23(ai-bj)

c

13(ai+bj) 

d

13(ai-bj)

answer is A.

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Detailed Solution

 

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xcm=m1x1+m2x2+m3x3m1+m2+m3i+m1y1+m2y2+m3y3m1+m2+m3j

 

=ma3mi+mb3mj

=13ai+bj

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