AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Three particles, each of mass M, are placed at the three corners of an equilateral triangle of side l. What is the force due to this system of particle on another particle of mass m placed at the midpoint of any side?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$\frac{4 G M m}{3 l^{2}}$

$\frac{4 G M m}{l^{2}}$

$\frac{3 G M m}{4 l^{2}}$

$\frac{G M m}{4 l^{2}}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Force on m due to masses at Q and R is zero. So, the net force is due to the mass at P.
Hence, $F_{3} = \frac{(G M m)}{{(P L)}^{2}}$

Now $P L = l \sin 60^{0} = l \frac{\sqrt{3}}{2}$
$F = \frac{4 G M m}{3 l^{2}}$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!