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Three photodiodes D₁, D₂ and D₃ are made of semiconductors having band gaps of 2.5eV, 2eV and 3eV, respectively. How many photodiodes will not be able to detect light of wavelength of $6000 \overset{0}{A}$ ?

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Detailed Solution

Energy of incident photon, $E = \frac{h c}{λ} = \frac{12400}{6000} e V = 2.06 e V$

For the incident radiation to be detected by the photodiode, energy of incident radiation photon should be greater than the band gap. This is true only for D₂. Therefore, only D₂ will detect this radiation.

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