Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Three photodiodes D1,D2,D3 are made of semiconductors having band gaps of 2.5ev, 2ev and 3ev which can detect light of wave length 6000Ao 

 

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

D2

b

D3

c

D1

d

All 
 

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given,

D1 photo diode's band gap = 2.5eV

D2photo diode's band gap = 2eV

D3photo diode's band gap = 3eV

The incident light's wavelength is 6000A. Consequently, incident light's energy is

E=hcλ

Substituting the values,

'E=6.6×10-34×3×1086×10-7×1.6×10-19 E=2.06eV

The incident radiation must have a photon energy greater than the band gap in order for the photodiode to detect it. This only applies to D2, though. Only D2 will thus be able to detect this radiation.

Hence the correct answer is D2.

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon