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Three plates A, B and C each of area 0.1m² are separated by 0.885 mm from each other as shown in the figure. A 10V battery is used to charge the system. The energy stored in the system is

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10^-2 $μ$ J

1 $μ$ J

10^-1 $μ$ J

10^-3 $μ$ J

answer is C.

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Detailed Solution

$\begin{array}{l} U = \frac{1}{2} C_{1} V^{2} + \frac{1}{2} C_{2} V^{2} \\ = \frac{1}{2} (C_{1} + C_{2}) V^{2} \end{array}$

$= \frac{1}{2} (\frac{8.85 \times 10^{- 12} \times 0.1}{0.885 \times 10^{- 3}} \times 2) \times 10^{2} = 10^{- 2} μ J$

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