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Q.

Three point charges +q, +q and –q are placed at the corners of an equilateral triangle of side 'a'. Another charge +Q is kept at the centroid.
Force exerted on Q is:

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a

$\frac{1}{4 {πε}_{0}} \frac{14 qQ}{a^{2}}$

b

$\frac{1}{4 {πε}_{0}} \frac{6 qQ}{a^{2}}$

c

$\frac{1}{4 {πε}_{0}} \frac{8 qQ}{a^{2}}$

d

$\frac{1}{4 {πε}_{0}} \frac{2 qQ}{a^{2}}$

answer is B.

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Detailed Solution

$F = (\frac{1}{4 {πε}_{0}} \frac{q}{r^{2}}) 2 where r = \frac{a}{\sqrt{3}}$

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