Three processes compose a thermodynamic cycle shown in the accompanying P-V, diagram of an ideal gas.Process 1→2 takes place at constant temperature, during this process 60 J of heat enters the system. Process 2→3 takes place at constant volume. During this process 40 J of heat leaves the system. Process 3→1 is adiabatic. What is the change in internal energy of the system during process 3→1?

1→2: isothermal ,ΔU12=02→3: isochoric, W=0⇒ Q23=ΔU23⇒−40=ΔU23 For a cyclic process, ΔU=0ΔU12+ΔU23+ΔU31=00+(−40)+ΔU31=00+(−40)+ΔU31=0ΔU31=+40J

Three processes compose a thermodynamic cycle shown in the accompanying P-V, diagram of an ideal gas.Process 1→2 takes place at constant temperature, during this process 60 J of heat enters the system. Process 2→3 takes place at constant volume. During this process 40 J of heat leaves the system. Process 3→1 is adiabatic. What is the change in internal energy of the system during process 3→1?

1→2: isothermal ,ΔU12=02→3: isochoric, W=0⇒ Q23=ΔU23⇒−40=ΔU23 For a cyclic process, ΔU=0ΔU12+ΔU23+ΔU31=00+(−40)+ΔU31=00+(−40)+ΔU31=0ΔU31=+40J

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Three processes compose a thermodynamic cycle shown in the accompanying P-V, diagram of an ideal gas.
Process 1 $\to$ 2 takes place at constant temperature, during this process 60 J of heat enters the system. Process 2 $\to$ 3 takes place at constant volume. During this process 40 J of heat leaves the system. Process 3 $\to$ 1 is adiabatic. What is the change in internal energy of the system during process 3 $\to$ 1?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

-40 J

-20 J

+20 J

+40 J

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} 1 \to 2 : isothermal, {ΔU}_{12} = 0 \\ 2 \to 3 : isochoric, W = 0 \\ \Rightarrow Q_{23} = {ΔU}_{23} \Rightarrow - 40 = {ΔU}_{23} \end{array}$

$For a cyclic process, ΔU = 0$

$\begin{array}{l} {ΔU}_{12} + {ΔU}_{23} + {ΔU}_{31} = 0 \\ 0 + (- 40) + {ΔU}_{31} = 0 \\ 0 + (- 40) + {ΔU}_{31} = 0 \\ {ΔU}_{31} = + 40 J \end{array}$