Q.

Three processes compose a thermodynamic cycle shown in the accompanying P-V, diagram of an ideal gas.

Process 12 takes place at constant temperature, during this process 60 J of heat enters the system. Process 23 takes place at constant volume. During this process 40 J of heat leaves the system. Process 31 is adiabatic. What is the change in internal energy of the system during process 31?

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a

+20 J

b

+40 J

c

-40 J

d

-20 J

answer is D.

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Detailed Solution

12: isothermal ,ΔU12=023: isochoric, W=0 Q23=ΔU2340=ΔU23

 For a cyclic process,  ΔU=0

ΔU12+ΔU23+ΔU31=00+(40)+ΔU31=00+(40)+ΔU31=0ΔU31=+40J

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