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Three reactions involving $H_{2} P {O_{4}}^{-}$ are given below:
(i) $H_{3} P O_{4} + H_{2} O \to H_{3} O^{+} + H_{2} P O_{_{4}}^{-}$
(ii) $H_{2} P O_{4}^{-} + H_{2} O \to H P O_{4}^{2 -} + H_{3} O^{+}$
(iii) $H_{2} P O_{4}^{-} + O H^{-} \to H_{3} P O_{4} + O^{2 -}$
In which of the above does $H_{2} P O_{4}^{-}$ act as an acid?

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(i) and (ii)

(i) only

(ii) only

(iii) only

answer is A.

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Detailed Solution

In $I I^{n d}$ equation $H_{2} P O_{4}^{-}$ give $H^{+}$ ion to the $H_{2} O$ therefore in the $I I^{n d}$ equation it act as an acid.

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