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Three resistance $4 Ω, 6 Ω a n d 10 Ω$ are connected in parallel and a p.d. of 30V is applied across the terminals of the combination. The current flowing through $6 Ω$ resistance is

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10 A

5 A

15 A

20 A

answer is B.

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Detailed Solution

Since they are connected in parallel combination the P.D across all the resistors is the same.

V=30 V and R=6 ohms

I=30/6=5 A

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