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Three resistances $1 Ω, 2 Ω and 3 Ω$ are connected in parallel. The ratio of currents passing through them when a p.d. is applied across the ends is

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1 : 1 : 1

6 : 3 : 2

2 : 3 : 6

1 : 2 : 3

answer is D.

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Detailed Solution

In parallel combination current is inversely proportional to resistance as potential difference is same for all

$i_{1} : i_{2} : i_{3} = \frac{1}{1} : \frac{1}{2} : \frac{1}{3} = 6 : 3 : 2$

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