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Q.

Three rods made of same material and having same cross-section have been joined as shown in fig. Each rod is of same length. The left and right ends are kept at 0°C and 90°C respectively. The temperature of the junction of the three rods will be
 

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a

60°C

b

45°C

c

20°C

d

30°C

answer is B.

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Detailed Solution

Let the temperature of junction be T. Then 
dQdt1=dQdt2+dQdt3
∴ KA(T−0)l=KA(90−T)l+KA(90−T)l
⇒T=180−2T⇒3T=180⇒T=60∘C

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