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Q.

Three rods of identical cross-section and lengths are made of three different materials of thermal conductivity K1,K2andK3, respectively. They are joined together at their ends to make a long rod (see figure). One end of the long rod is maintained at 100 C  o and the other at 0 C  o (see figure). If the joints of the rod are at 70 C  o and 20 C  o in steady state and there is no loss of energy from the surface of the rod, the correct relationship between K1,K2andK3 is :

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a

K1:K2=5:2,K1:K3=3:5

b

K1>K2>K3

c

K1:K3=2:3,K2:K3=2:5

d

K1<K2<K3

answer is A.

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Detailed Solution

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As the rods are identical, so they have same length (l) and area of cross-section (A). They are connected in series. So, heat current will be same for all rods.

Heat current =ΔQΔtAB=ΔQΔtBC=ΔQΔtCD

10070K1Al=7020K2Al=200K3Al

K110070=K27020=K3200K130=K250=K320

K110=K26=K315K1:K2:K3=10:6:15

K1:K3=2:3.

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