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Q.

Three similar light bulbs are connected to a constant voltage dc supply as shown in figure. Each bulb operates at normal brightness and the ammeter (of negligible resistance) registers a steady current. The filament of one of the bulbs  breaks. What happens to the ammeter reading and to the brightness of the remaining bulbs? 

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a

Ammeter Reading-increases, Bulb brightness-increases

b

Ammeter Reading-decreases, Bulb brightness-unchanged

c

Ammeter Reading-increases, Bulb brightness-unchanged

d

Ammeter Reading-unchanged, Bulb brightness-unchanged

answer is D.

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Detailed Solution

Suppose V is the voltage of the supply and R is the resistance of each bulb. Now, S1  nor  Rp=R/3 and current in ammeter is I=V/Rp=3V/R, provided all three bulbs are working properly. If one bulb has broken down, then RpR2  and   I=2VR

Therefore, current decreases and since current through each bulb is V/R, the same as before, brightness of bulbs is not affected.

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