Three small spheres each carrying a positive charge Q are placed on the circumference of a circle of radius to form an equilateral triangle. The electric field intensity at the centre of the circle will be.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

$\frac{3 Q}{r}$

$\frac{1}{v^{2}} \frac{Q}{r^{2}}$

$\frac{3 Q}{r^{2}}$

Zero

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given data: on the edge of a circle of radius, three tiny spheres with positive charges are arranged to make an equilateral triangle.

Concept used: Electric field

Detailed solution:

The electric field at the centre by

$E = \frac{k q}{r^{2}}$

The three electric fields are $120 °$ apart and have equal magnitudes.

The net Electric field at center is zero.

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE