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Q.

Three solid cubes have a face diagonal of 4 2 cm   each. Three other solid cubes have a face diagonal of 8 2 cm   each. All the cubes are melted together to form a big cube. Find the side of the cube formed (in cm).


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a

10  

b

12  

c

13  

d

15   

answer is B.

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Detailed Solution

Given:
Three solid cubes having an equal length of the face diagonal given by,
d 1 =4 2  cm  
Let us assume the length of the side of the square of these three solid cubes be  a 1   .
We know that the face of a cube is a square and the diagonal of the square is  2   times the length of the side of the square.
So, we get, for first three cubes,
d 1 = 2 × a 1  
Substituting  d 1 =4 2  cm   we get,
4 2 = 2 × a 1  
Solving this, we get,
a 1 =4 cm  
So, the volume of the three cubes = 3 × volume of one cube
V 1 =3× a 1 3  
Substituting  a 1 =4  we get,
V 1 =3× 4 3 V 1 =3×64 V 1 =192  cm 3  
Similarly,
For three other solid cubes having the same length of the face diagonal given by-
d 2 =8 2  cm  
Let us assume the length of the side of the square of these three solid cubes be  a 2   .
Then for the three other cubes, the length of the diagonal of the square
d 2 = 2 × a 2  
Substituting  d 2 =8 2  cm   we get,
8 2 = 2 × a 2  
Solving this, we get,
a 2 =8 cm  
So, the volume of the three cubes = 3 × volume of one cube
V 2 =3× a 2 3  
Substituting  a 2 =8  we get,
V 2 =3× 8 3 V 2 =3×512 V 2 =1536  cm 3  
IMG_256
Now, the total volume of all the six cubes combined V= V 1 + V 2  
Substituting the values,
V=192+1536 V=1728  cm 3  
Let the side of this big cube be a then, its volume is,
V= a 3 1728= a 3 a=12 cm  
Therefore, the side of the big cube formed after melting all cubes is  12cm   and the correct option is 2.
 
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