Three solutions of HCl having normality 12N, 6N and 2N are mixed to obtain a solution of 4N which among the following volume ratio is correct for the above three solutions

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1:2:6

1:1:5

2:1:9

1:2:4

answer is B.

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Detailed Solution

$\begin{array}{l} N_{1} V_{1} + N_{2} V_{2} + N_{3} V_{3} = NR (V_{1} + V_{2} + V_{3}) \\ \Rightarrow 12 x 1 + 6 x 2 + 2 x 6 = N_{R} (9) \Rightarrow N_{R} = 4 \end{array}$

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