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Three sparingly soluble salt that have same solubility products are given below
I. $A_{2} X$ II. AX III. ${AX}_{3}$
Their solubilities order in a saturated solution will be

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II>I>III

III>II>I

III>I>II

II>III>I

answer is A.

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Detailed Solution

$S_{I} = {[\frac{K_{sp}}{4}]}^{1 / 3} for A_{2} X; S_{II} = \sqrt{K_{sp}} for AX$

$S_{III} = {[\frac{K_{sp}}{27}]}^{1 / 4} for {AX}_{3}$

$∴ S_{II} > S_{I} > S_{III}$

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