Three sparingly soluble salts M₂X, MX and MX₃, have same value of solubility product. Their solubillities follow the order

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MX₃ > MX > M₂X

MX > MX₃ > M₂X

MX > M₂X > MX₃

MX₃ > M₂X > MX

answer is D.

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Detailed Solution

$\large {M_2}X\left( s \right) \rightleftharpoons \mathop {{M_2}X\left( {aq} \right)}\limits_{{S_1}} \xrightarrow{{}}\mathop {2{M^ + }\left( {aq} \right)}\limits_{2{S_1}} + \mathop {{X^{ - 2}}\left( {aq} \right)}\limits_{{S_1}}$

$\large {K_{sp}} = {\left( {2{S_1}} \right)^2}{S_1} = 4S_1^3$

$\large MX\left( s \right) \rightleftharpoons \mathop {MX\left( {aq} \right)}\limits_{{S_2}} \xrightarrow{{}}\mathop {{M^ + }\left( {aq} \right)}\limits_{{S_2}} + \mathop {{X^ - }\left( {aq} \right)}\limits_{{S_2}}$

$\large {K_{sp}} = {\left( {{S_2}} \right)^2}$

$\large MX_3\left( s \right) \rightleftharpoons \mathop {{MX_3}\left( {aq} \right)}\limits_{{S_3}} \xrightarrow{{}}\mathop {{M^{+3} }\left( {aq} \right)}\limits_{{S_3}} + \mathop {3{X^ - }\left( {aq} \right)}\limits_{3{S_3}}$