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Q.

Three tankers contain 403 liters , 434 liters and 465 liters of diesel respectively. Find the maximum capacity of the container that can measure the diesel of the three containers the exact number of times.



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a

 31

b

 12

c

 15

d

 20  

answer is A.

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Detailed Solution

Concept- we will take the HCF of three tankers to find the maximum capacity out of the HCF of 403,434,465, find the common factor in all 3 HCF .Compare them to find maximum capacity .We will find HCF by prime factorization method.
Amount of diesel present in the first tank =403 liters
Amount of diesel present in second tank =434 liters
Amount of diesel poresent in third tank =465 liters
Maximum capacity = HCF(403,434,465)
We will find HCF by prime factorization.
Prime factorization of 403,434,465.
403=1×13×31
434=1×2×7×31
465=1×3×5×31
Now, HCF 403,434,465=31
So, here we got the maximum measuring capacity as 31 liters.
Hence, the correct answer is option 1.
 
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