three uncharged capacitors having $60 \mu F, 30 \mu F$ and $10 \mu F$ are connected to each other as shown. Calculate the potential at the point $O$.

According to Kirchhoff's Junction Law (KJL), they cannot accumulate at the junction $\left(O\right)$, so

$\sum q_{{ }_0}=0$, where $q=C△V$

Let $V_0$ be the potential of junction $O$, then

$$\begin{gathered} 60\left(6-V_0\right)+10\left(2-V_0\right)+30\left(3-V_0\right)=0 \\ \Rightarrow 360+20+90=\left(60+10+30\right)V_0 \\ \Rightarrow V_0=\frac{470}{100} \\ \Rightarrow V_0=4.7 V \end{gathered}$$