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Three voltmeters, all having different resistances, are joined as shown. When some potential difference is applied across A and B, their readings are $V_{1}, V_{2}, V_{3} :$

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$V_{1} = V_{2}$

$V_{1} \neq V_{2}$

$V_{1} + V_{2} = V_{3}$

$V_{1} + V_{2} \neq V_{3}$

answer is B, C.

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Detailed Solution

In parallel combination potential difference are same
So $V_{1} + V_{2} = V_{3}$ Here $V_{1} a n d V_{2}$ are in series but their resistances are different
So $\begin{array}{l} V_{1} = i R_{1} \\ V_{2} = i R_{2} \\ V_{1} \neq V_{2} \end{array}$ ,

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