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Three waves are propagating in same direction and pass through a point simultaneously. The variation of electric field with time is as $E_{1} = E_{0} \cos ω t, E_{2} = 2 E_{0} \sin ω t$ and $E_{3} = 5 E_{0} \cos (ω t + 53^{0});$ and intensity due to first wave at that point is $I_{0}$ . Then

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Resultant amplitude of their interference is $5 E_{0}$

Resultant amplitude of their interference is $\sqrt{20} E_{0}$

Resultant intensity of interference is $25 I_{0}$

Resultant intensity of interference is $20 I_{0}$

answer is B, D.

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Detailed Solution

$5 E_{0} \times (\frac{3}{5}) = 3 E_{0} 5 E_{0} \times (\frac{4}{5}) = 4 E_{0} ∴ A_{r} = \sqrt{{(2 E_{0})}^{2} + {(4 E_{0})}^{2}} = E_{0} \sqrt{20} ∴ I_{r} = I_{0} \times {(\frac{A_{r}}{A})}^{2} = 20 I_{0}$

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