Q.

Threshold frequency of a metal is 6 × 1014 s-1. The kinetic energy of an electron emitted when a radiation of frequency 1015 s-1 hits the metal is

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a

2.65 × 10-19 J

b

2.65 × 10-22 J

c

5.3 × 10-21 J

d

5.3 × 10-20 J

answer is B.

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Detailed Solution

 K.E of photo electrons :

K.Emax=h(v-vº)             =6.625 × 10-34 J.s(1015s-1 - 6 × 1014 s-1)             =6.625 × 10-34J.s(10 × 1014 s-1 - 6 × 1014s-1)             =6.625 × 10-34×4×1014 J             =2.65×10-19J

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